what-will-be-the-output-of-the-program class-bitshift- { ----public-static-void-main(string-[]-args)- ----{ --------int-x-=-0x80000000; --------system.out.print(x-+-"-and--"); --------x-=-x->>>-31; --------system.out.println(x); ----} } -5e8ac7f29f5f597f4815a162

What will be the output of the program?

class BitShift 
{
    public static void main(String [] args) 
    {
        int x = 0x80000000;
        System.out.print(x + " and  ");
        x = x >>> 31;
        System.out.println(x);
    }
}

-2147483648 and 1
0x80000000 and 0x00000001
-2147483648 and -1
1 and -2147483648

Explanation

Option A is correct. The >>> operator moves all bits to the right, zero filling the left bits. The bit transformation looks like this:

Before: 1000 0000 0000 0000 0000 0000 0000 0000

After: 0000 0000 0000 0000 0000 0000 0000 0001

Option C is incorrect because the >>> operator zero fills the left bits, which in this case changes the sign of x, as shown.

Option B is incorrect because the output method print() always displays integers in base 10.

Option D is incorrect because this is the reverse order of the two output numbers.